已知x+1/x=3,求2x的4次方+2/x的4次方

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已知x+1/x=3,求2x的4次方+2/x的4次方

2x的4次方+2/x的4次方
=2x的4次方+2/x的4次方+4-4
=2(x²+1/x²)²-4
=2(x²+1/x²+2-2)²-4
=2[(x+1/x)²-2]²-4
=2×(3²-2)²-4
=2×49-4
=94

2x^4+2/x^4
=2(x^4+1/x^4)
=2[(x^2+1/x^2)^2-2]
=2(x^2+1/x^2)^2-4
=2[(x+1/x)^2-2]^2-4
=2[3^2-2]^2-4
=2*7^2-4
=98-4
=94

x与1/x互为倒数,平方后中间项为常数;
(x+1/x)²=x²+1/x²+2
把 x+1/x=3代入
9=x²+1/x²+2
x²+1/x²=7
再平方,(x²+1/x²)²=x^4+2+1/x^4
49=x^4+2+1/x^4
所以 x^4+1/x^4=47。