f'(x)在(0,1)上有界,证明f(x)在(0,1)上有界

f(x)在(-∞,+∞) 二阶可导,f(x)/x=1,且f''(x)>0,证明f(x)>=x f'(x)在(0,1)上有界,证明f(x)在(0,1)上有界 证明f(x)=1/x+2,在x>0时,f(x)单调递减 函数F（x)满足下列性质 f(a+b)=f(a)f(b) f(0)=1 f(x)在x=0处可导 证明对任意X有 f'(x)=f'(0)f(x) 证明:若函数f(x)在满足关系式f'(x)=f(x),且f(0)=1,则f(x)=e^x 证明：若函数f(x)在(-oo,+oo)内满足关系式f'(x)=f(x),且f(0)=1,则f(x)=e^x 证明:若函数f(x)在满足关系式f'(x)=f(x),且f(0)=1,则f(x)=e^x如题 证明若函数f(x)在R内可导且f'(x)=f(x),f(0)=1,则f(x)=e^x 证明:若函数f(x)在(-∞,+∞)内满足不等式f'(x)=f(x),且f(0)=1,则f(x)=e∧x 设函数f(x)在(-∞,+∞)可导,且满足f(0)=1,f'(x)=f(x),证明f(x)=e^x 设函数f(x)=x-xlnx.证明f(x)在区间(0,1)上是增函数. 设函数f(x)在（-∞,+∞)内有定义,f(0)不等于0,f(xy)=f(x)f(y),证明：f(x)=1 有一个函数f(x),f(x)=f'(x),f(0)=1,证明：f(x)=e^x 高等数学f(x+y)=f(x)+f(y)/1-f(x)f(y),求f(x)f(x+y)=f(x)+f(y)/1-f(x)f(y),则f(x)=tan(ax)怎么证明?f(x)在（-∞,+∞）上有定义,且f'(x)=a(a不等于0) f(x)在(0,1)上连续,f(0)=f(1)=0,证明必存在f''(x)=2f'(x)/(1-x) f(x)在〔0,1〕上连续.f(0)＝f(1)证明存在x使f(x)＝f(x＋0.5) 证明:f(x)在[0,1]连续,f(0)=f(1),则存在x0(0 f'(x)在(0,1)有界,怎么证明f(x)在(0,1)有界