作业帮化简此题
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/31 02:48:53
化简此题
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1