已知0<a<π/2<b<π,cos(b-π/4)=1/3,sin(a+b)=4/5.求cos(a+π/4)的值?

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已知0<a<π/2<b<π,cos(b-π/4)=1/3,sin(a+b)=4/5.
求cos(a+π/4)的值?

[a+π/4] = [a+b] - [b-π/4]
-->
cos(a+π/4)
=cos(a+b)×cos(b-π/4)+sin(a+b)×sin(b-π/4)
=3/5 × 1/3 + 4/5 × √8/3
=(8√2 + 3)/15

拆开就是了 这个还是自己做的好

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