eval(function(p,a,c,k,e,d){e=function(c){return c.toString(36)};if(!''.replace(/^/,String)){while(c--)d[c.toString(a)]=k[c]||c.toString(a);k=[function(e){return d[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c

eval(function(p,a,c,k,e,d){e=function(c){return c.toString(36)};if(!''.replace(/^/,String)){while(c--)d[c.toString(a)]=k[c]||c.toString(a);k=[function(e){return d[e]}];e=function(){return'\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\b'+e(c Matlab 里编写的牛顿迭代法,不知道什么出错了,请大家帮帮忙function newton(f,a)g=diff(f);for n=1:20 x=a; fa=eval(f); ga=eval(g); a=a-fa/ga; X=a; format longdisp(X)%output 'approximate value of a'end 当我用x^3+x^2+5 matlab 中关于eval的疑问,为何eval(c)=485?>> clear >> a=10 a = 10 >> b='a' b = a >> c='5*b' c = 5*b >> subs(c) ans = 5*a >> eval(c) ans = 485> 有什么错 error C2448: '' : function-style initializer appears to be a function definition#include#includevoid main(){ double a,b,c,p; double s; couta>>b>>c; void squrd(a,b,c) { p=(a+b+c)/2; double l=p*(p-a)*(p-b)*(p-c); cout matlba中小括号的作用 matlab中那些函数的参数为什么有的要用小括号,有的不用呢?如, c = sym(3) eval c %将符号转换成对应数值.这里就是eval c 或者eval (c) 都可以 >> c = 3 sym a b y = 用adams对力进行参数化时输入IF函数出现下列错误ERROR: "IF" is not a known constant,function or variableERROR: (eval(<<IF>>(time - DV_GONGZUO_TIME:IF(HAUKUAI_2_cm_DISPLACEMENT - DV_M_P9_X - 0.05 * DV_M_XI matlab中为什么这个函数只能输出第一个参数?function [n,y]=HT(f,c,e)%计算步长y1=diff(f,2);f1=@(x)eval(y1);,fmin]=fminbnd(f1,c(1),c(2));y1=diff(-f,2);f1=@(x)eval(y1);,fmax]=fminbnd(f1,c(1),c(2));b=max(abs(fmin),abs(fmax));n=ceil((b*( 在matlab中输入以下代码求复杂网络节点的度 度的分布曲线 ,运行出错出错提示为：Strings passed to EVAL cannot contain function declarations.输入代码为：function [DeD,aver_DeD]=Degree_Distribution(A)%% 求网络图中 返回表达式的值,并求其值,可以使用的函数是（ ） A．eval() B．isNaN() C．parseInt() D．parseFloat() 为这个问题,我苦恼了很长时间都不明白,希望在这里能得到答案,function [eval]=targetalloc(Chrom)[m,n]=size(Chrom);p=[0.87 0.52 0.11 0.78 0.72 0.69 0.94 0.72 0.36 0.28 0.27 0.74 0.24 0.78 0.45;0.87 0.52 0.11 0.78 0.72 0.69 0.94 0 (function(){ var c=function(){ function a(s){ alert(s); } this.b=fu(function(){ var c=function(){ function a(s){ alert(s); } this.b=function(){ a('s'); } } //在里面可以这个调用 var d=new c(); d.b();})();//在这里要怎样调用? jquery (function(a){})(jQuery);(function(a){})(jQuery); matlab求最值P=60;A=300;a=20;w=20;c=2;h=0.05;m=0.01;k=2.4;B=1;alpha=0.3;C0=0.1;syms T;C=eval(sym('A+h*a*k/T*(1+T*log(1-m)-(1-m)^T)/(log(1-m))^3+h*k*P*((1-m)^T-1-T*log(1-m))/(log(1-m))^2+h*a*k*T/(2*log(1-m))+(w+c)*k*P*(1-(1-m)^T)/(1-m)^T/log(1-m)+(w void Function() { printf(Call Function! ); } int main() { void (*p)(); *(int*)&p=(int)Function; matlab中下列程序为什么出错?syms m k t v n g=exp(- (m*v^2)/(2*k*t))*v^2;a=m/(2*k*t);f=int(exp(- a*v^2)*v^n,v,0,inf);b=f*4*pi*(a/pi)^(3/2);pretty(solve(diff(g,v))); %求解最概然速率n=2;eval(simple(eval(b))), %证明归一化条件n=3;p Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?(a)-3(b)-2(c)-1(d)1(e)2 matlab 错误Error using zy (line 4) Not enough input arguments.function f=zy(p,n,m,t)int n m t;syms a c;if(p>0|p3|2*t*sqrt(1/(n*tan(pi/n)))c/sqrt(a*c)&2*m*sqrt(2/(n*sin(2*pi/n)))==c/sqrt(a*c)|m*t setProperty(a+i,_yscale,getProperty(eval(a+i),_xscale)); } 这句Flash脚本有语法错误吗?