用公式法解2(x平方-7x-10)-1=0

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用公式法解2(x平方-7x-10)-1=0

2(x² - 7x - 10)- 1 = 0
2x² - 14x - 21 = 0
x = (14 ± √(14² + 4 * 4 * 21))/4
= (14 ± √532)/4
= (7 ± √143)/2

解答如下:
2(x² - 7x - 10)- 1 = 0
2x² - 14x - 21 = 0
x = (14 ± √(14² + 4 *2 * 21))/4
= (14 ± √364)/4
= (14 ± 2√91)/4
= 7± (√91/2)

2(x² - 7x - 10)- 1 = 0
2x² - 14x - 21 = 0
x = (14 ± √(14² + 4 *2 * 21))/4
= (14 ± √364)/4
= (14 ± 2√91)/4
= 7± (√91/2)

1、公式法:
原方程可写为:2x平方-14x-21=0
对应模型:ax平方+bx+c=0
x1=(-b+开根号(b平方+4ac))/2a
=(14+开根号(-14平方+4*2*-21))/(2*2)=
x2=(-b+开根号(b平方-4ac))/2a
=(14+开根号(-14平方-4*2*-21))/(2*2)=