∫sinx/(1+cos^2x)dx不定积分
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 18:45:18
∫sinx/(1+cos^2x)dx不定积分
∫(1+sinx) / cos^2 x dx
求不定积分∫(1+sinx) / cos^2 x dx
∫sinx/(1+cos^2x)dx不定积分
求不定积极分∫sin^3(x)cos^2(x)dx
∫(sinx)/(cos∧2 x)dx怎么解?
求不定积分∫(cos x)^2 /sinx dx
∫(sinx/cos立方x)dx
∫(sinx/cos^3x)dx
求不定积分 1.∫ x/(1+(x^2))dx 2.∫cos^2 x sinx dx 1.∫ x/(1+(x^2))dx 2.∫cos^2 x sinx dx
∫±π/2 (sinx/1+cos平方x)dx
∫(0,π/2)cos(sinx)dx
∫sinx^2cos^3dx
求不定积分 sinx/cos^3x dx答案是1/(2cos^2x)+c
∫(sinx-x^2)dx
∫x/(sinx)^2dx
∫ x/(sinx)^2dx
∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷
这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx =