(28-2x)(20-x)=494
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(28-2x)(20-x)=494
(28-2x)(20-x)=494
2x^2-68x+560=494
2x^2-68x+66=0
x^2-34x+33=0
(x-1)(x-33)=0
x1=1 x2=33
如果本题有什么不明白可以追问,
560-28x-40x+2x²=494
2x²-68x+66=0
x²-34x+33=0
(x-1)(x-33)=0
x1=1 , x2=33
(28-2x)(20-x)=494
30%X-30%X-[(X-30%X)×20%-2]-30%X=28怎么解
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x+10+x-20+2x+x/2=370
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15X(4X-8)-5X(2X+10)=6X(5X-20)
f(x)=x^2+x (x
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(x^2-3x+1) (x^2+3x+2)( x^2-9x+20)= -30求X
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