Math Problem,Welcome To Answer?If the equation m(x-1)=2005-n(x-2) for x has infinite roots,then m的2005次方+n的2005次方=?This is a special question of Grade six.Waiting for an understandable answer,thank you all!请使用中文回答本问题,
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Math Problem,Welcome To Answer?
If the equation m(x-1)=2005-n(x-2) for x has infinite roots,then m的2005次方+n的2005次方=?
This is a special question of Grade six.Waiting for an understandable answer,thank you all!
请使用中文回答本问题,
m(x-1)=2005-n(x-2) for x has infinite roots
意思为这个式子有无限个根
将m(x-1)=2005-n(x-2)凑一下:
(m+n)(x-1)=2005+n
因为这个式子有无限个根
所以m+n=0 2005+n=0
所以m=2005 n=-2005
所以m的2005次方+n的2005次方=0
如果这个方程有无数解 那么 m=-n 且-m=2005+2n
解得m=2005 n=-2005
所以 m的2005次方+n的2005次方=0
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