两道计算,过程要~[22/3-(49/12-36/20+77/30-91/42+105/56)]/225.6*69.32+138.64*0.05+639.2*0.43谢谢

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 15:19:05

两道计算,过程要~
[22/3-(49/12-36/20+77/30-91/42+105/56)]/22
5.6*69.32+138.64*0.05+639.2*0.43
谢谢

(22/3-49/12+9/5-77/30+13/6-15/8)/22
=(22/3-23/12-77/30-1/24)/22
=(22/3-47/24-77/30)/22
=1/3-47/528-7/60
=13/60-47/528
=337/2640
5.6*69.32+138.64*0.05+639.2*0.43
=5.6*69.32+138.64*0.05+63.92*4.3
=69.32*1.3+69.32*0.1
=69.32*1.4
=97.048

第一题是不是63/20?
如果是则
[22/3-(49/12-63/20+77/30-91/42+105/56)]/22
=(22/3)/22-(49/12-63/20+77/30-91/42+105/56)/22
=1/3-(7*7/12-7*9/20+7*11/30-7*13/42+7*15/56)/22
=1/3-(7*7/12-7*9/20+7*1...

全部展开

第一题是不是63/20?
如果是则
[22/3-(49/12-63/20+77/30-91/42+105/56)]/22
=(22/3)/22-(49/12-63/20+77/30-91/42+105/56)/22
=1/3-(7*7/12-7*9/20+7*11/30-7*13/42+7*15/56)/22
=1/3-(7*7/12-7*9/20+7*11/30-7*13/42+7*15/56)/22
=1/3-7*(7/12-9/20+11/30-13/42+15/56)/22
=1/3-7*[(1/3+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1/7-1/8)]/22
=1/3-7*(1/3-1/8)/22
=1/3-7*(5/24)/22
=176/528-35/528
=47/176
这里最后是不是693.2*0.43?
5.6*69.32+138.64*0.05+693.2*0.43
=5.6*69.32+2*69.32*0.05+69.32*10*0.43
=69.32*(5.6+2*0.05+10*0.43)
=69.32*(5.6+0.1+4.3)
=69.32*10
=693.2

收起