求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]=3x+1

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求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]=3x+1

(1)7x-[x-1/2(x-1)]=2/3(x-1)
42x-6x+3(x-1)=4(x-1)
36x=(x-1)
35X=-1
X=-1/35
(2)3/4[4/3(1/2x-1/4)-16]=3x+1
(1/2x-1/4)-12=3x+1
2x-1-48=12x+4
10x=-53
x=-53/10