Who can help me?标准状况下,体积为6.72L的NO和NO2的混合气体,质量为11.88g,则NO和NO2的体积比为?o

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Who can help me?
标准状况下,体积为6.72L的NO和NO2的混合气体,质量为11.88g,则NO和NO2的体积比为?
o

6.72L气体即0.3mol
然后用十字交叉法
0.3mol NO 9g
0.3mol NO2 13.8g
NO 9 1.92 2
11.88 ------ = -
NO2 13.8 2.88 3
解得2:3
如果你不懂十字交叉 也可以设NO Xmol NO2 Ymol
X+Y=0.3
30X+46Y=11.88
解出X,Y即可

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