表达虚数式Express the complex number in trigonometric form.3 - 3iA) 3*(cos5π/4 +isin5π/4)B) 3*root of2*(cos7π/4 +isin7π/4)C) 3*(cos7π/4 +isin7π/4)D) 3*root of2*(cos5π/4 +isin5π/4)(root of 2 就是根号2)我的步骤是:3*(1-i)
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表达虚数式
Express the complex number in trigonometric form.
3 - 3i
A) 3*(cos5π/4 +isin5π/4)
B) 3*root of2*(cos7π/4 +isin7π/4)
C) 3*(cos7π/4 +isin7π/4)
D) 3*root of2*(cos5π/4 +isin5π/4)
(root of 2 就是根号2)
我的步骤是:3*(1-i)
那么,1-i 就可以得出 cos7pai/4 前面不应该是个3吗?
但我用计算机算出来,cos7pai/4 应该 * 3根号2才等于 3..
求这类题目的正确解题步骤,
也请把含有这部分的中文的书名给我一份..
就是B呀 cos7pi/4=根号2/2
sin7pi/2=-根号2/2
两者乘以根号2就成为了
1-i
在乘以3就是3(1-i)
所以对啦 没错撒
表达虚数式Express the complex number in trigonometric form.3 - 3iA) 3*(cos5π/4 +isin5π/4)B) 3*root of2*(cos7π/4 +isin7π/4)C) 3*(cos7π/4 +isin7π/4)D) 3*root of2*(cos5π/4 +isin5π/4)(root of 2 就是根号2)我的步骤是:3*(1-i)
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