(1)120+290÷58*16 (2)5/6*11+5/6 (3)(2/3-2/5)*(1/8+1/12)简算
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(1)120+290÷58*16 (2)5/6*11+5/6 (3)(2/3-2/5)*(1/8+1/12)
简算
(1)120+290÷58*16
=120+29*10÷(29*2)*16
=120+5*16
=120+80
=200
(2)5/6*11+5/6
=5/6*(11+1)
=5/6*12
=10
(3)(2/3-2/5)*(1/8+1/12)
=2*(1/3-1/5)*1/4*(1/2+1/3)
=1/2*2/15*5/6
=1/18
(1)120+290÷58*16
=120+290*16÷(29*2)
=120+(290÷29)*(16÷2)
=120+10*8
=120+80=200
(2)5/6*11+5/6
=(5/6)*(11+1)
=12*5/6
=5*12/6
=5*2=10
(3)(2/3-2/5)*(1/8+1/12)
=(10/15-6/15)*(3/24+2/24)
=(4/15)*(5/24)
=(4/24)*(5/15)
=(1/6)*(1/3)
=1/18
(1)=120+5*16=120+80=200
(2)=55/6+5/6=60/6=10
(3)=2(1/3-1/5)*(3/24+2/24)=(4/15)*(5/24)=1/18
(1)120+290÷58*16 =120+50×16=120+800=920
(2)5/6*11+5/6 =55/6+5/6=60/6=10
(3)(2/3-2/5)*(1/8+1/12)=(10/15-6/15)*(3/24+2/24)
=4/15*5/24=1/18
(1)120+290÷58*16 (2)5/6*11+5/6 (3)(2/3-2/5)*(1/8+1/12)简算
怎样简便就怎样算:5/6*11加5/6 120+290/58*16 (2/3-2/5)*(1/8+1/12) 9/8/【3/4-(7/16-1/4)】
1485+290÷58×16怎么简便运算
(111*58-148*16)÷37=
58=()÷16=15()=()÷56=()(填小数)58=()÷16=15()=()÷56=()(填小数)
解方程(1)8/5÷(x-0.45)=16/3、(2)120*40%+12*9/20+x=120(写出过程)
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(1)33°14′5″+27°19′58″=?(2)32°16′4″÷4=?
(4/7+16/9+58/11+38/13)÷(1/7+8/3+4/11+41/13),
(58+370)÷(64÷16) 简便计算
简算.(1)102×96÷16 (2)1000÷(125÷4)
58÷8表示( )
(-81)÷4又2分之1×(-9分之4)÷(-16)
计算; 1.(-16)÷(-1又16分之1)÷(-64) 2.(-4分之5)÷0.25÷(-4分之15)3.(-125)÷(-3分之2)÷(-2分之3)
(-81)÷2又4分之1+9分之4÷(-16)过程,
(-81)÷2又4分之1+9分之4÷(-16)
(1)1.9×130%= (2)0.3×100%=(3)16×100%=(4)15×18.0%= (5)9×112%= (6)5×24%=(6)1.8÷36%= (7)0.3+120%= (8)0.798÷21%= (7)1-68%= (8)25%+3.72= (9)37.2÷6.2%= (10)180%÷9= (11)120
1.1整数和整除的意义30÷ 6 120÷ 5 75÷ 6 2÷ 6 8÷ 16 48÷ 12 1.5÷ 3 9÷ 0.25分成两类(可重复)1被除数能被除数整除的 2能够除尽的