π/4

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π/4

sin(α+β)=-sin[π+(α+β)]=-sin(π/4+α+3π/4+β)=-[sin(π/4+α)cos(3π/4+β)+ cos(π/4+α)sin(3π/4+β)]=-[4/5*-12/13+ -3/5*5/13]=63/65

kπ+π/4 π/4 π/4 π/4 π/4 化简/π-5/+/4-π/+/-π+3.1/ |π-3|+|π-4|咋么算求|4-π|+|3.14-π| 数值：sin9π/4+cos2π/3+tan5π/4 数值：sin9π/4+cos2π/3+tan5π/4 求值：tan(2π+π/4 )+tan(4π+π/4)+tan(6π+π/4).+tan(2010π+π/4)= 已知π/4 已知π/4 若π/4理由若3π/4 已知π/4 若π/4 已知π/4