化学求带过程解!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g.急!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g of sodium react with excess water
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化学求带过程解!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g.
急!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g of sodium react with excess water
用40除以23求得钠的摩尔量,钠与水出氢气,钠与氢气摩尔比2比一,再用气体状态方程求体积,OK?
2Na + 2H2O = NaOH + H2
2 1
40/23 n mol
n= (40/23)÷2= 20/23
由PV=nRT 得V=nRT/P=( 20/23×8.314×280)÷96 = 21.1(L)
化学求带过程解!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g.急!how many liters of hydrogen gas will be produced at 280K and 96kPa if 40g of sodium react with excess water
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