D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as

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D.P.J.
这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as a party

D.P.J.=Democratic Party of Japan 日本民主党

D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as 二维数组的等价问题*若有以下定义和赋值语句,则与&s[i][j]等价的是().int s[2][3]={0},(*p)[3],i,j;p=s; i=j=1;A) *(*(p+i)+j)B) *(p[i]+j)C) *(p+i)+j D) (*(p+i))[j ] 这段程序输出p,q,i,j的值是多少#includevoid main(){int i=5,j=5,p,q;p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j);printf(%d,%d,%d,%d ,p,q,i,j);} #include main() { int j,a[]={1,3,5,7,9,11,13,15},*p=a+5; for(j=3; j; j--)#include main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3; j; j--){ switch(j){ case 1:case 2:printf(%d,*p++); break;case 3:printf(%d,*(--p));}}}答案是9911,是怎样 int j,a[]={1,3,5,7,9,11,13,15,#include main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3; j; j--){ switch(j){ case 1:case 2:printf(%d,*p++); break;case 3:printf(%d,*(--p));}}}答案是9911,是怎样来? 对于这个答案谁能给我个解释?对于这个程序的答案是15,22,8,8,这个答案小弟我始终不明白,#includemain(){int i=5,j=5,p,q; p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j); printf(%d,%d,%d,%d,p,q,i,j);} (1/2)b m p p p j l d f h f a f j h s d f y f d v h h s x g i g d g ,中文是什 main(){int i=5,p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j);printf(%d,%d,%d,%d,p,q,i,j);} 求matlab语句解答,D()=y1()是什么意思,下边的abs是求绝对值得吗for j=1:2*p*lfor m=1:10f=cos(t-pi*(1-p)*(j-1)/(p*l))*exp(-i*m*t);y1(m)=int(f,t,-pi/(2*p*l)+pi*(j-1)/(p*l),pi/(2*p*l)+pi*(j-1)/(p*l));D(j,m)=y1(m);endendB=sum(D);B=abs( 与P字母最搭的英文名,P在最后?例如:“D.空格J”的J 地质年代中这几个字母代表什么?Q N E K J T P C D 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l N D Z Z D S S T Y J A P H L D M? Z D G C W C Z D N Y Z Y L D Y X L K , W X G N H H , J X Z女朋友发的短信这是什么意思,像是汉字首拼音 破解下!这是汉子首拼音! C语言 p=(i++)+(i++)+(i++); q=(++j)+(++j)+(++j);void main(){  int i=5,j=5,p,q;  p=(i++)+(i++)+(i++);  q=(++j)+(++j)+(++j);  printf(%d,%d,%d,%d,p,q,i,j);  }对P=(i++)+(i++)+(i++)应理解为三个i相加,故P值为15.然后i再 a d g .j m p 组成一个单词 model is ill lingo,高手帮帮忙!1下面的是我写的 但是怎么改都有错!model:sets: varei/1..7/:t,s; varej/1..4/:size,num,p1,p2,g,b,q; links(varei,varej):x,p,m,d;endsets!目标函数;min=@sum(links:m(i,j)*((p(i,j)-p1(j))*b(j)+g(j))*t(i) q f t j q f j d e p w q #include void swap(char *a,char *b){ char *t;t=a;a=b;b=t;}main(){ char i=3,j=5,*p=&i,*q=&j;swap(p,q);printf(%d %d ,i,j);}(1)printf(%d %d ,i,j);改为printf(%d %d “,*p,*q); 结果一样,同样是:3 5(2)定义为char,没有错误,只