A bag of cement of weight 345 N hangs from three wires as shown in the figure below.Two of the wires make angles θ1 = 55.1° and θ2 = 24.1° with the horizontal.If the system is in equilibrium,calculate the tension T1.Answer:
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A bag of cement of weight 345 N hangs from three wires as shown in the figure below.
Two of the wires make angles θ1 = 55.1° and θ2 = 24.1° with the horizontal.If the system is in equilibrium,calculate the tension T1.
Answer:
一袋水泥的重量345牛顿,挂起从三个电线所显示的数字如下.
两个角度线作出 θ1 = 55.1 ° , θ2 = 24.1 °的水平.如果系统是平衡,计算表# t1的紧张局势.
345/(sin54.1+tan24.1*cos54.1)=345/(0.63879026519264+0.8302652823681*0.76938091807317)=270.04168566654349630919509604684
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A bag of cement of weight 345 N hangs from three wires as shown in the figure below.Two of the wires make angles θ1 = 55.1° and θ2 = 24.1° with the horizontal.If the system is in equilibrium,calculate the tension T1.Answer:
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