用因式分解法解方程1.x^2=2x2.(x+1)^2-(2x-3)^2=03.x^2-6x+8=04.(1+√2)x^2-(1-√2)x=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 01:19:18

用因式分解法解方程1.x^2=2x
2.(x+1)^2-(2x-3)^2=0
3.x^2-6x+8=0
4.(1+√2)x^2-(1-√2)x=0

1.x^2=2x
x²-2x=0
x(x-2)=0
x=0或x=2
2.(x+1)^2-(2x-3)^2=0
(x+1+2x-3)(x+1-2x+3)=0
(3x-2)(4-x)=0
x=3/2或x=4
3.x^2-6x+8=0
(x-2)(x-4)=0
x=2或x=4
4.(1+√2)x^2-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x=0或x=(1-√2)/(1+√2)
x=0或x=(1-√2)²/(1-2)
即:x=0或x=2√2-3

2.(x+1)^2-(2x-3)^2=(x+1+2x-3)(x+1-2x+3)=(3x-2)(4-x)=0 得:x1=2/3,x2=4
3.x^2-6x+8=(x-2)(x-4)=0 得:x1=2,x2=4
4.(1+√2)x^2-(1-√2)x=? buhuile!