求下列函数的反函数:y=2+arccos(2x-1)1）y=2+arccos(2x-1)2）y=(1/3)arctan(x/2)

求下列函数的反函数:y=2+arccos(2x-1)
1）y=2+arccos(2x-1)
2）y=(1/3)arctan(x/2)

y=2+arccos(2x-1)
y-2=arccos(2x-1)
cos(y-2)=2x-1
cos(y-2)+1=2x
x=1/2(cos(y-2)+1)
y=1/2(cos(x-2)+1)
y=(1/3)arctan(x/2)
3y=arctan(x/2)
tan(3y)=x/2
x=2tan(3y)
y=2tan(3x)