因式分解x^2+3xy+2y^2+4x+5y+3 由于x^2+3xy+2y^2=(x+2y)(X+y),而4x+5y拆为x+2y和3(x+y),而3=1乘3由十字相乘法,可得原式=(x+2y+3)(x+y+1)但我看不懂【由十字相乘法,可得原式=(x+2y+3)(x+y+1)】,
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因式分解x^2+3xy+2y^2+4x+5y+3 由于x^2+3xy+2y^2=(x+2y)(X+y),而4x+5y拆为x+2y和3(x+y),而3=1乘3
由十字相乘法,可得原式=(x+2y+3)(x+y+1)
但我看不懂【由十字相乘法,可得原式=(x+2y+3)(x+y+1)】,
[(x+2y)+3]* [(x+y)+1]你把小括号先看成整体.这样不就好理解了
x^2+3xy+2y^2+4x+5y+3
= x^2+(2+1)xy+2y^2+4x+5y+3
=x^2+2xy+xy+2y^24x+5y+3
=x(x+2y)+y(x+2y)+4x+5y+3
= (x+y)(x+2y)+4x+5y+3
=(x+y)(x+2y)+x+2y+3x+3y+3
=(x+y)(x+2y)+(x+2y)+3(x+y+1)
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x^2+3xy+2y^2+4x+5y+3
= x^2+(2+1)xy+2y^2+4x+5y+3
=x^2+2xy+xy+2y^24x+5y+3
=x(x+2y)+y(x+2y)+4x+5y+3
= (x+y)(x+2y)+4x+5y+3
=(x+y)(x+2y)+x+2y+3x+3y+3
=(x+y)(x+2y)+(x+2y)+3(x+y+1)
=(x+y+1)(x+2y)+3(x+y+1)
=(x+y+1)(x+2y+3)
x^2+3xy+2y^2
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