已知a^x-y*a^2y+1=a^11,且b^x-1*b^4-y=b^5,求(x^2)*y的值

已知a^x-y*a^2y+1=a^11,且b^x-1*b^4-y=b^5,求(x^2)*y的值

a^(x-y)*a^(2y+1)=a^11
a^(x-y+2y+1)=a^11
a^(x+y+1)=11
x+y+1=11.(1)
b^(x-1)*b^(4-y)=b^5
b^(x-1+4-y)=b^5
b^(x-y+3)=5
x-y+3=5.(2)
x=6,y=4
(x^2)*y=(6^2)*4=144