(y-4)²=(y-4)(3y-1)用因式分解法解方程怎么做?

(y-4)²=(y-4)(3y-1)用因式分解法解方程怎么做?

(y-4)²=(y-4)(3y-1)
(y-4)²-(y-4)(3y-1)=0
(y-4)(y-4-3y+1)=0
(y-4)(-2y-3)=0
y1=4 y2=-3/2
如果本题有什么不明白可以追问,

(y-4)²=(y-4)(3y-1)
(y-4)²-(y-4)(3y-1)=0
(y-4)(y-4-3y+1)=0
(y-4)(-2y-3)=0
-(y-4)(2y+3)=0
所以
y=4或y=-3/2