-25x^3y+20x^2y^2-4xy^3先化简,再求值.(-5ab^2)^3+65(ab)^2 ·(-b^2)·(-a) 其中a=1,b=1
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-25x^3y+20x^2y^2-4xy^3
先化简,再求值.
(-5ab^2)^3+65(ab)^2 ·(-b^2)·(-a) 其中a=1,b=1
-25x^3y+20x^2y^2-4xy^3
=-xy(25x^2-20xy+4y^2)
=-xy(5x-2y)^2
(-5ab^2)^3+65(ab)^2 ·(-b^2)·(-a)
=-125a^3b^6+65a^3b^4
=-5a^3b^4(25b^2-13)
其中a=1,b=1
原式=-5a^3b^4(25b^2-13)=-5(25-13)=-5X12=-60
xy(-25x^2+20xy-4y^2)
第二题=-125a^3b^6+65a^2b^2*(-b^2)*(-a)
=-125a^3b^6-65a^3b^4
=-5a^3b^4(25b^2+13)
因为a=1,b=1,所以,原式=-5*1*1(25*1+13)
=-5*38
=-190
^代表几次方,*表示乘号
-25x^3y+20x^2y^2-4xy^3=xy(-25x^2+20xy-4y^2)=-xy((5x)^2-2*5x*2y+(2y)^2)=-xy(5x-2y)^2
(-5ab^2)^3+65(ab)^2 ·(-b^2)·(-a)=-125a^3b^6+65a^3b^4=5a^3b^4*(-25b^2+13)=5*(-25+13)=-60
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