(1)|x-2y+1|+|2x-y-5|=0 (2)把x^3-4x分解因式,结果为_____(1)|x-2y+1|+|2x-y-5|=0,则x+y的值为
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(1)|x-2y+1|+|2x-y-5|=0 (2)把x^3-4x分解因式,结果为_____
(1)|x-2y+1|+|2x-y-5|=0,则x+y的值为
(1)因为绝对值不会是负数,所以只有0+0才可能等于0
所以x-2y+1=2x-y-5=0
可解得x=11/3 y = 7/3
则x+y=6
(2)x^3-4x=x(x^2-4)=x(x+2)(x-2)
(1)|x-2y+1|+|2x-y-5|=0
x-2y +1 =0
2x -y -5 = 0
3x -3y = 4
x - y =4/3
x -2y = -1
y = 7/3
x = (4+7) /3 = 11/3
(2)把x^3-4x分解因式,结果为x (x+2)(x-2)
x^3-4x
=x(x²-4)
=x(x+2)(x-2)
第一题
x-2y+1 = 0
2x-y-5 = 0
所以 x = 11/3 y = 7/3
第二题
x³-4x = x(x²-4) = x(x+2)(x-2)
希望对你有帮助,还有不懂可以来问我
(1)y=7/3 x=11/3 (2)x(x+2)(x-2)
太简单了吧
(1)|x-2y+1|+|2x-y-5|=0
x-2y +1 =0
2x -y -5 = 0
3x -3y = 4
x - y =4/3
x -2y = -1
y = 7/3
x = (4+7) /3 = 11/3
不会可追问
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