一道八年级上的二次根式计算题-2²×√8+3√2(3-2√2)-1/(1+√2)

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一道八年级上的二次根式计算题
-2²×√8+3√2(3-2√2)-1/(1+√2)

-2²×√8+3√2(3-2√2)-1/(1+√2)
=-4*2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11

-2²×√8+3√2(3-2√2)-1/(1+√2)
=-4*2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11

=-4×2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11