因式分解解下列方程(3X-1)²-49=04(X-3)²=25(X-2)²

来源:学生作业帮助网 编辑:作业帮 时间:2024/03/29 03:28:07

因式分解解下列方程
(3X-1)²-49=0
4(X-3)²=25(X-2)²

(3X-1)²-49=0
(3X-1+7)(3X-1-7)=0
3(X+2)(3X-8)=0
X=-2,X=8/3
4(X-3)²-25(X-2)²=0
[2(X-3)+5(X-2)][2(X-3)-5(X-2)]=0
(7X-16)(-3X+4)=0
X=16/7,X=4/3

(3x-1)^2-7^2=0, [(3x-1)+7][(3X-1)-7]=0, (3X-1+7)(3X-1-7)=0
(3X+6)(3X-8)=0, X1=-2, X2=8/3
2^2(X-3)^2=5^2(X-2)^2, [2(X-3)]^2-[5(X-2)]^2=0, [2(X-3)+5(X-2)][2(X-3)-5(X-2)]=0
(2X-6+5X-10)(2X-6-5X+10)=0, (7X-16)(4-3X)=0
X1=16/7, X2=4/3

(3X-1)²-49=0
→(3X-1)²-7²=0
→(3X-1+7)(3X-1-7)=0
→ (3X+6)(3X-8)=0
X=3/8或者-2
4(X-3)²=25(X-2)²
→[2(x-3)]²-[5(x-2)]²=0
→ [2(x-3)+5(x-2)][2(x-3)-5(x-2)]=0
→ (7x-16)(-3x+4)=0
X=16/7或4/3