因式分解:x²+2x+1-y²
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因式分解:x²+2x+1-y²
答:
x²+2x+1-y²
=(x+1)²-y²
=(x+y+1)(x-y+1)
原式=(x+1)^2-y^2
=(x+1+y)(x+1-y)
因式分解:x²+2x+1-y²
答:
x²+2x+1-y²
=(x+1)²-y²
=(x+y+1)(x-y+1)
原式=(x+1)^2-y^2
=(x+1+y)(x+1-y)