1/1X3=1/2(1-1/3),1/3X5=1/2(1/3-1/5),1/5X7=1/2(1/5-1/7),.计算 1/1X3+1/3X5+1/5X7...见下1/1X3=1/2(1-1/3),1/3X5=1/2(1/3-1/5),1/5X7=1/2(1/5-1/7),.计算 1/1X3+1/3X5+1/5X7...+1/(2n-1)(2n+1)=(n为大于1的自然数)
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1/1X3=1/2(1-1/3),1/3X5=1/2(1/3-1/5),1/5X7=1/2(1/5-1/7),.计算 1/1X3+1/3X5+1/5X7...见下
1/1X3=1/2(1-1/3),1/3X5=1/2(1/3-1/5),1/5X7=1/2(1/5-1/7),.计算 1/1X3+1/3X5+1/5X7...+1/(2n-1)(2n+1)=(n为大于1的自然数)
1/1X3+1/3X5+1/5X7...+1/(2n-1)(2n+1)
=1/2[1-1/3+1/3-1/5+1/5-1/7+.+1/(2n-1)-1/(2n+1)]
=1/2[1-1/2n+1]
=n/2n+1
1/2乘以(1-1/3+1/3-1/5+1/5-1/7。。。。。。)=1/4n-2
这题我也正好在做,也不懂耶,谢啦……
1/2乘以(1-1/3+1/3-1/5+1/5-1/7。。。。。。)=1/4n-2
1/1X3+1/3X5+1/5X7...+1/(2n-1)(2n+1)=(n为大于1的自然数)
=1/2x(1-1/3+1/3-1/5+1/5-1/7+1/7+.......-1/2n-1+1/2n-1-1/2n+1)
=1/2(1-1/2n+1)
=n/2n+1
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