f(x)=sqrt(4-x^2)的原函数怎么求
令x = 2cost(0≤t则sqrt(4-x^2) dx = sqrt[4-4(cost)^2] = sqrt[(4sint)^2] = 2sint(0≤tdx = d(2cost) = -2sint dt所以f(x) dx = -4(sint)^2 dt积分,将t换回x可得f(x)的原函数