ysinx
y'=e^ysinx的微分方程通解e^(-y)dy=sinxdx-d[e^(-y)]=-dcosx∴e^(-y)=cosx+c
ysinX=cos(X—y)求导数dy/dX
ysinx-cos(x+y)=0,求dy/dx应用复合函数求导方法,y′sinx+ycosx+(1+y′)sin(x+y)=0,(sinx+sin(x+y))y′+ycosx+sin(x+y)=0,y′=-(ycosx+sin(x+y))/
解微分方程(siny-ysinx)dx+(xcosy+cosx)dy=0(siny-ysinx)dx+(xcosy+cosx)dy=0sinydx+ydcosx+xdsiny+cosxdy=0dxsiny+dycosx=0xsiny+yco
求微分方程y'+ysinx=e^cosx的通解注意到(yexp(-cosx))'=y'exp(-cosx)+yexp(-cosx)sinx=exp(-cosx)(y'+ysinx)所以(yexp(-cosx))'=1yexp(-cosx)=
微分方程y'+ysinx=e^(-cosx)的通解∵齐次方程y'+ysinx=0==>y'=-ysinx==>dy/y=-sinxdx==>ln│y│=cosx+ln│C│(C是积分常数)==>y=Ce^cosx∴齐次方程是y=Ce^cos
微分方程y'cosx+ysinx=1的通解通解为y=sinx+Ccosx,将方程变形为标准形式套公式即可.y'+P(x)y=Q(x)对应公式是y=e^(-∫P(x)dx)[∫Q(x)e^(∫P(x)dx)dx+C]补充:标准形式为y'+yt
求方程的解ysinx+(dy/dx)cosx=1,先计算齐次方程y'/y=tgx的通解,得到lny=lncosx+c1=ln(c2cosx),得到y=ccosx;同时根据非齐次方程的一个特解y=sinx,得到总的通解为y=ccosx+sin
求微分方程y'+ysinx=e^cosx的通解∵齐次方程y'+ysinx=0==>y'=-ysinx==>dy/y=-sinxdx==>ln│y│=cosx+ln│C│(C是积分常数)==>y=Ce^cosx∴齐次方程是y=Ce^cosx(
求y'cosx+ysinx=1的通解通解为y=sinx+Ccosx,将方程变形为标准形式套公式即可.y'+P(x)y=Q(x)对应公式是y=e^(-∫P(x)dx)[∫Q(x)e^(∫P(x)dx)dx+C]补充:标准形式为y'+ytanx
微分方程求解:y'-ysinx-y^2+cosx=0原方程化为(y+sinx)'=y(y+sinx),令z=y+sinx,z'=z(z-sinx),即z'+zsinx=z^2这是贝努利方程,就可求解了.
y^2-ysinx=e^-cosx的通解mathematica的答案:
z=e^ysinx求二阶混合偏导数z‘’xy
高数题设e(x+y)-ysinx=0求y(,)括号内为上标设e(x+y)-ysinx=0求y(,)括号内为上标两边关于x求一阶导y'*e^(x+y)-y'sinx-ycosx=0y'=ycosx/(e^(x+y)-sinx)隐函数在某些点不
ysinx+cos(x-y)=0,求dy/dx|(x=π/2)两边对x求导:dy/dxsinx+ycosx-sin(x-y)(1-dy/dx)=0,将x=π/2带入已知方程得到y,再把x、y带入上式求得结果
dy/dx=-(2xcosy+y^2*cosx)/(2ysinx-x^2*siny)求解微分方程参考答案:停车坐爱枫林晚,霜叶红于二月花.x=y
设xsiny+ysinx=y求y'siny+xcosy*y'+y'*sinx+ycosx=0为啥cosy后面还加个y'sinx前面加个y'?(ysinx)’=sinx+ycosx
已知ysinx-cos(x+y)=0,求在点(0,π)的dy/dx值两边对x求导y'*sinx+ycosx-[-sin(x+y)*(1+y')]=0y'(sinx+sin(x+y))=y(1-cosx)y'=[1-cosx]/[sinx+s
求微分方程cosx(dy/dx)+ysinx-1=0的通解,y'+tanx×y=secx,一阶非齐次线性方程,套用通解公式,y=cosx(tanx+C)书上有公式啊p(x)=tanxQ(x)=secxy=公式(打不出来了)答案:y=cosx
求下列方程所确定的函数的导数ysinx-cos(x-y)=0ysinx=cos(x-y)同时求导数y'sinx+ycosx=(x-y)'sin(y-x)y'sinx+ycosx=(1-y')sin(y-x)y'sinx+ycosx=sin(