sin4x积分
化简:1+sin4X-cos4X分之1+sin4X+cos4X要写清楚,发20分的积分.原式=(sin2x^2+cos2x^2+2sin2xcos2x+cos2x^2-sin2x^2)/(sin2x^2+cos2x^2+2sin2xcos2
∫兀到0√(sin²x/2-sin4x/2)dx的定积分看我的分析,不算精彩,但是可以解题,请叫我雷锋.
化简:(1+sin4x-cos4x)/(1+sin4x+cos4x)-(1+sin4x+cos4x)/(1+sin4x-cos4x)(1+Sin4x+Cos4x)/(1+Sin4x-Cos4x)=[1+Sin4x+2(Cos2x)^2-1]
化简(1+sin4x+cos4x)/(1+sin4x-cos4x)原式=(sin2x^2+cos2x^2+2sin2xcos2x+cos2x^2-sin2x^2)/(sin2x^2+cos2x^2+2sin2xcos2x-cos2x^2+s
(1+cos4x+sin4x)/(1-cos4x+sin4x)化简
化简1+cos4X+sin4X\(1-cos4X+sin4X)等会我算
cos4x-sin2x-sin4x=?已经最简,化简不了了.
求函数的周期y=(cos4x+sin4x)/(cos4x-sin4x)解析:y=(cos4x+sin4x)/(cos4x-sin4x)=(1+tan4x)/(1-tan4x)=tan[(π/4)+4x](注:两角和的正切公式)因为正切型函数
化简(1+sin4X-cos4X)÷(1+sin4X+cos4X)(1+sin4X-cos4X)=(sin2x)^2+(cos2x)^2+2sin2xcos2x-(cos2x)^2+(sin2x)^2=2(sin2x)^2+2sin2xco
y=[cos4x+sin4x]/[cos4x-sin4x]求最小正周期分子分母同时除以cos4x,得y=(1+tan4x)/(1-tan4x)=[tan(π/4)+tan4x]/[1-tan(π/4)tan4x]=tan(4x+π/4)从而
证明COS2X=COS4X-SIN4Xcos²x+sin²x=1所以cos2x=cos²x-sin²x=(cos²x-sin²x)(cos²x+sin²x)=c
sin4x=sinx解三角方程sin4x-sinx=0化为:2cos(5x/2)sin(3x/2)=0,因此有:cos(5x/2)=0--->5x/2=kπ+π/2-->x=2kπ/5+π/5sin(3x/2)=0--->3x/2=kπ--
sin4x=sinx怎么解,sin4x-sinx=02sin﹙3x/2﹚cos﹙5x/2﹚=0x=﹙2/3﹚kπ或x=﹙2/5﹚kπ﹢π/5
解三角方程sin4x=sinxsin4x-sinx=02cos(5x/2)sin(3x/2)=0得:cos(5x/2)=0,或sin(3x/2)=0得:5x/2=kπ+π/2,或3x/2=kπ即x=(2kπ+π)/5或2kπ/3,这里k为任
解三角方程sin4x=cosxsin4x=cosx2sin2xcos2x=cosx4sinxcosx(2cosxcox-1)/2=cosx2sinxcosx(2cosxcosx-1)=cosx[1]cosx=0,x=圆周率pi/+kpi[2
解三角方程:sin4x=cosxsin4x=2sin2xcos2x=4sinxcosxcos2x=cosx所以4sinx(1-2sin^2x)=0所以sinx=0或sin2=根号2/2所以x=0或45sin4x=cosx=sin(90+2k
sin2x比sin4X为多少?∵sin4X=sin(2x+2x)=2sin2xcos2x∴sin2x/sin4x=1/2cos2x
解不等式:sin4x+cos4xctg2x>1sin4x=2sin2x*cos2xcos4x=1-2(sin2x)^2ctg2x=cos2x/sin2x所以sin4x+cos4xctg2x=2sin2x*cos2x+[1-2(sin2x)^
解三角方程sin4x=sinxOO4x=x+2kTT或4x=x+(2k+1)TTx=2kTT/3或x=(2k+1)TT/3你好:sin4x=2sin2xcos2x=4sinxcosxcos2x=sinx1.sinx=0x=kTT2.sinx
用cosX表示:sin4X-sin2X+cos2Xsin4x-sin2x+cos2x=2sin2x*cos2x-2sinxcosx+2cos^2x-1=4sinxcosx(2cos^2x-1)-2sinxcosx+2cos^2x-1剩下的就