log(2)3log(3)8

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4^[log(2)3+log(4)8]

4^[log(2)3+log(4)8]4^[log(2)3+log(4)8]=4^[log(2)3+3/2]=2^[2log(2)3+3]=2^[log(2)9+3]=9*(2^3)=72

已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2

已知log(2)[log(3)(log(4)x)]=log(3)[log(4)(log(2)y)]=0,求x+y的值log(2)[log(3)(log(4)x)]=0log(3)(log(4)x)=1log(4)x=3x=64log(3)[

(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路

(log(4)3+log(8)3)(log(3)2+log(9)8)怎么个思路原式=[log(2的平方)3+log(2的三方)3][log(3)2+log(3的平方)2的三方]=[0.5log(2)3+三分之一log(2)3][log(3)

化简:(log^3 2+log^9 2)(log^4 3+log^8 3)

化简:(log^32+log^92)(log^43+log^83)我认为^后面的数字表示底数了.(log^32+log^92)(log^43+log^83)=(log^32+1/2log^32)(1/2log^23+1/3log^23)=(

(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路

(log(4)3+log(8)3)(log(3)2+log(9)2)怎么个思路用换底公式logab=lnb/lna(log(4)3+log(8)3)(log(3)2+log(9)2)=(ln3/(2ln2)+ln3/(3ln2))(ln2/

对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(

对数计算1.{log(4)(3)+log(8)(3)}X{log(3)(2)+log(9)(2)}2.{log(2)(3)}X{log(3)(4)+log(9)(2)}3.(lg2)^+1g2X1g5+1g501.[log4(3)+log8

log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃....

log(3)4*log(4)8*log(8)M=log(2)16M是多少呃....用换底公式log(3)4*log(4)8*log(8)M=(lg4/lg3)*(lg8/lg4)*(lgM/lg8)=lgM/lg3log(2)16=log(

[log(5)8]*[log(32)5]+log(9)8/log(3)2

[log(5)8]*[log(32)5]+log(9)8/log(3)2[log(5)8]*[log(32)5]+log(9)8/log(3)2=log5(8)/log5(32)+log3^2(2^3)/log3(2)换底公式=log32(

求值:(log(4)3+log(8)3)×(log(3)2+log(9)2)+log(2)(2^5)

求值:(log(4)3+log(8)3)×(log(3)2+log(9)2)+log(2)(2^5)¼原式=(1/2log(2)3+1/3log(2)3)×(log(3)2+1/2log(3)2)+5/4=5/6log(2)3×3

[log(4)3+log(8)3][log(3)2+log(9)2]-log(1/2)32∧1/4过

[log(4)3+log(8)3][log(3)2+log(9)2]-log(1/2)32∧1/4过程详细点,log(4)3是log以4为底3的对数,log(4)3+log(8)3用换底公式,再加loga(x^n)=nlogax=ln3/l

求[log(2)9+log(4)9+log(8)27+……+log(2^n)3^n]*log(9)n

求[log(2)9+log(4)9+log(8)27+……+log(2^n)3^n]*log(9)n次根号32(n∈N*)的值.要具体过程,[log(2)9+log(4)9+log(8)27+……+log(2^n)3^n]*log(9)n次

求等式log(2)3*log(3)4*log(4)5*log(5)6*log(6)7*log(7)m

求等式log(2)3*log(3)4*log(4)5*log(5)6*log(6)7*log(7)m=log(3)9时m的值?log(2)3*log(3)4*log(4)5*log(5)6*log(6)7*log(7)m=log(3)9根据

计算:2log(2)3-log(2)9/8

计算:2log(2)3-log(2)9/8原式=log(2)3²-log(2)3²/8=log(2)(3²÷9/8)=log(2)8=32log23-log2(9/8)=log29-log29+log28=32

log(8)9 / log(2)3 这要用什么公式啊`?

log(8)9/log(2)3这要用什么公式啊`?换底公式:log(a)b=lgb/lga证明:设log(a)b=t则a^t=b,两边取以10为底的对数lga^t=lgbtlga=lgb所以t=lgb/lga所以log(a)b=lgb/lg

(log(8)9)/log(2)3

(log(8)9)/log(2)33log(8)9=2/3log(2)3因为8=2的3次幂9等于3的2次幂所以log(8)9=2/3log(2)3(系数可以提前,查性质中有)所以原式等于2/3

计算:8^(1-log(83))(27^(2/3))-log(32)

计算:8^(1-log(83))(27^(2/3))-log(32)8^(1-log(8,3))=8^1÷8^log(83)=8/3

log(2)9log(3)4等于

log(2)9log(3)4等于答案等于:4

log(2)9×log(3)4

log(2)9×log(3)4log(2)9=2log(2)3log(3)4=2log(3)2=》4log(2)3*log(3)2=>4*(log(2)3*(1/(log(2)3)))=4//由换底公式 log(a)(b)=log

[log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)

[log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=?左边=(lg2x/lg4)*(lg3y/lg2x)*(lgz/lg3y)=lgz/lg4右边=2log8x(8x)=2所以l

有关对数的计算题(log(4)3+log(8)3)(log(3)2+log(9)2)=?

有关对数的计算题(log(4)3+log(8)3)(log(3)2+log(9)2)=?(log(4)3+log(8)3)(log(3)2+log(9)2)=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)=(lg3/2