log2

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log2(log2

log2(log2log2(log216)=log2(4)=2

log2 6-log2 3

log26-log23log26-log23=log2(6/3)=log22=1

log2^6-log2^3

log2^6-log2^3log2^6-log2^3=6log2-3log2=3log2

log2 (log2 16)=?

log2(log216)=?=2

log2(4)/log2(3)

log2(4)/log2(3)换底公式=lig2(2²)/(lg3/lg2)=2/(lg3/lg2)=2lg2/lg3=lg2²/lg3=lg4/lg3=log3(4)log2(4)/log2(3)=2/log2(3)=

[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[

[log21]+[log22]+[log23]+[log24]+[log25]+...+[log21024]=?[x]表示不超过x的最大整数2为底答案是82042*1+2^2*2+2^3*3+.+2^9*9用一个错位相减就可以得到答案log

log2 3/log2 5等于log2 3-log2 5么?

log23/log25等于log23-log25么?真数的商可以写成对数的差,这是两个对数的商,㏒2(3)/㏒2(5)=㏒3(5).

计算:log2(log2 32-log2 3/4+log2 6)

计算:log2(log232-log23/4+log26)log2(log232-log23/4+log26)=log2(log2(32/(3/4)*6))=log2(log2(256))=log2(8)=3

已知log2

已知log2题目有点问题啊.log2a的话0

若log2

若log2你问的是loga(2)a在哪

log2是什么意思

log2是什么意思log2?楼主说的这个真的没有.有ln2,e(自然底数)为底数,2为真数;lg2,10为底数,2为真数.如果a^n=b,那么log(a)(b)=n.其中,a叫做“底数”,b叫做“真数”,n叫做“以a为底b的对数”.好像没有

log2 5/4+log2 5

log25/4+log25log25/4+log25=log25/4×5=log24=2

log2^(x^log2^x)=?

log2^(x^log2^x)=?log2{x^[log2(x)]}=log2(x)log2(x)=[log2(x)]^2

log2 27/log2 9=

log227/log29=换底公式:logab/logac=logcb所以原式=log927=log3²3³=(3/2)*log33=3/2

log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?l

log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!log2(3)×log2(4)=log2(7)吗?不对!l

log2 SQR(7/48)+log2 12 -1/2log2 42

log2SQR(7/48)+log212-1/2log242log2√(7/48)+log212-1/2log242=log2√(7/48)+log2(12)-log2√42=log2√(7/48)*12/√42=log2√7*144/48

log2 SQR(7/48)+log2 12 -1/2log2 48

log2SQR(7/48)+log212-1/2log248log2SQR(7/48)+log212-1/2log248=0.5log27+0.5log248+log212-1/2log248=0.5log27+log212=log2100

log4(log2^x)=log2(log4^x)求log2^x

log4(log2^x)=log2(log4^x)求log2^x如果log4(log2^x)是表示外面的log以4为底,而里面的log以10或其它数(>0)为底的话,则log4(log2^x)=[log2(log2^x)]/2=log2(l

log2^(4^7*2^5)+log2^6-log2^3

log2^(4^7*2^5)+log2^6-log2^3log2^(4^7*2^5)+log2^6-log2^3=log2^(4^7*2^5*6/3)=log2^(2^14*2^5*2)=log2^(2^(14+5+1))=14+5+1

求值:log2(32)+log2(6)-log2(3/4)

求值:log2(32)+log2(6)-log2(3/4)log2(32)+log2(6)-log2(3/4)=log2(32x6÷3/4)=log2(256)=8