limtan(xy)y
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xy'=y+xy的xdy=(y+xy)dxdy/y=((1+x)/x)dxln|y|=ln|x|+x+cy=±e^(ln|x|+x+c)其中c是常数
|x|/x+y/|y|+xy/|xy|=由题可知x,y都不等于0.下面分x>0,y>0x>0yx0x四种情况去绝对值,这样就得到你要的答案啦.我复制楼下的结果来的,这是正确的.当x>0;y>0时,|x|/x+y/|y|+xy/|xy|=1+
【x(xy-xy)-y(x-xy)】÷3xy2xy
-x-3xy+y-(x2+3xy-y2)=-(x2+3xy+2.25y2-3.25y2)=-((x+1.5)2-3.25y2)结束了?不会分解分解肯定不对你们老师出的题?对啊题出错了?有人分解出来了?全部展开-(x2+3xy-y2)收起
xy-1+x-yxy-1+x-y=XY+X-Y-1(加法交换律)=(XY+X)-(Y+1)=X(Y+1)-(Y+1)(提取公因式X)=(Y+1)(X-1)(提取公因式Y+1)这样可以么?原式=x-1+y(x-1)=(x-1)(y+1)xy-
集合{(x,y)|xy不对,还有两条轴上也有成立
计算:(xy-x²)×x-y/xy这题少括号了吧.
XY(XY-X2)乘以------------X-YXY(XY-X^2)(X-Y)=X^2Y(X-Y)(X-Y)=(X-Y)(X^2Y-1)
4xy平方-4xy-y立方4xy平方-4xy-y立方=4xy²-4xy-y³=y(4xy-4x-y²)
x^2-xy/xy-y^2约分
(xy+1)(x+1)(y+1)+xy(xy+1)(x+1)(y+1)+xy=(xy+1)(xy+1+x+y)+xy=(xy+1)(xy+x+1)+y(xy+1)+xy=(xy+1)(xy+x+1)+y(xy+1+x)=(xy+x+1)(x
xy^2-2xy+2y-4xy(y-2)+2(y-2)下步不写了能看懂吧?
【xy-x²】*xy/x-y解(xy-x²)xy/(x-y)=x²y(y-x)/[-(y-x)]=-x²y
xy^2-2xy+2y-4xy^2-2xy+2y-4=xy(y-2)+2(y-2)=(y-2)(xy+2)
对xy求导,为什么等于y+xy'这是求导法则,要证明要用到极限去证明才行,一两句话说不清楚为什么?公式是这样的:[f(x)g(x)]'=f'(x)g(x)+f(x)g'(x)记得就行了.
XY+Y=YX问:XY是多少89
(xy+1)(x+1)(y+1)+xy是(xy+1)(x+1)(y+1)+xy=(xy+1)[(xy+1)+(x+y)]+xy=(xy+1)^2+(x+y)(xy+1)+xy=(xy+1+x)(xy+1+y)
xy'+y=-xy^2的通解y'为一次导?xy'/y^2+1/y=-x-x(1/y)'+1/y=-x1/y=t-xt'+t=-x(t'x-t)/x^2=1/x(t/x)'=1/xt/x=lnx+ct=xlnx+cx1/y=xlnx+cxy=
(2xy-y)-2xy化简=2xy-y-2xy=-y
化简4xy-y-xy+x原式=3xy+x-y答案是3xy+x-y,此类题只需将相同字母前的系数相加减,统称合并同类项,望采纳3xy+x-y原式=3Xy+x-y