y根号x

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化简:(根号X/Y)+(根号y/x)

化简:(根号X/Y)+(根号y/x)先把分母都变成根号XY再相加得到(X+Y)/根号XY再把分母有理化得到(X+Y)*根号XY/XY啊哈,简单(根号X/Y)+(根号y/x)根号XY/Y+根号xy/x平方就好啦!

化简(x-y)/(根号x+根号y)

化简(x-y)/(根号x+根号y)(x-y)/(根号x+根号y)=((根号x)²-(根号y)²)/(根号x+根号y)=(根号x-根号y)(根号x+根号y)(根号x+根号y)=根号x-根号y答案根号x-根号yx-y=(根号

x+y/根号X-根号Y-2XY/X乘根号Y-Y乘根号X

x+y/根号X-根号Y-2XY/X乘根号Y-Y乘根号Xx+y/根号X-根号Y-2XY/X乘根号Y-Y乘根号X=x+y/根号X-根号Y-2根号XY/根号X-根号Y=x-2根号XY+y/根号X-根号Y=根号X-根号Y

根号x-根号y分之x+y-x根号y-y根号x分之2xy

根号x-根号y分之x+y-x根号y-y根号x分之2xy化简:根据文字理解,是这样的吗?√x-x/√y+y-x√y-y(2xy)/√x

x根号x+x根号y/xy-y^2)-(x+根号xy+y/x根号x-y根号)y

x根号x+x根号y/xy-y^2)-(x+根号xy+y/x根号x-y根号)y(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)=[x(√x+√y)/[y(√x-√y)(√x+√y)]-[x+√(xy)+y]/{

2根号XY×根号Y\X(Y

2根号XY×根号Y\X(Y2根号XY×根号Y\X(Y2根号XY×根号Y\X(Y=2√(XY×Y\X)=2√Y²=-2Y5根号45×2\3根号2\3=5×3√5×2\3×√6/3=5×3×2/3/3×√5×√6=10√30/3

根号X*Y等于根号X*根号y吗?理由

根号X*Y等于根号X*根号y吗?理由当X,Y大于等于零时,根号X*Y等于根号X*根号y当X,Y小于零时,根号X*Y成立,根号X*根号y不存在

(x根号y-y根号x)除以根号xy,

(x根号y-y根号x)除以根号xy,(x根号y-y根号x)除以根号xy=(根号x^2y-根号y^2x)除以根号xy=根号x-根号y注:x^2为x的平方原式=(x*y^(1/2))/xy-(y*x^(1/2))/xy=y^(-1/2)-x^(

已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)

已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)原式=√y/(√2y-√y)-√y/(√2y+√y)=√y/[√y(√2-1)]-√y/[√y(√2+1)]=1/(√2-1)-1/(√2+1)=(√2+1)/(√2+

已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)

已知x=2y,化简根号y/(根号x-根号y)-根号y/(根号x+根号y)把X=2Y代入得:原式=√Y*√(2Y)-√Y*√Y-√Y*√(2Y)-√Y*√Y=-2Y=-X

已知x=2y,化简:根号y/根号x -根号y -根号y/根号x +根号y

已知x=2y,化简:根号y/根号x-根号y-根号y/根号x+根号y

已知x =2y 化简(根号y/根号x -根号y )-(根号y/根号x +根号y)

已知x=2y化简(根号y/根号x-根号y)-(根号y/根号x+根号y)(根号y/根号x-根号y)-(根号y/根号x+根号y)={根号y(根号x+根号y)}/(x-y)-{根号y(根号x-根号y)}/(x-y)=(y+y)/(x-y)因为x=

根号xy除以x-y分之根号x+根号y 即:根号xy/(根号x+根号y)/(x-y)

根号xy除以x-y分之根号x+根号y即:根号xy/(根号x+根号y)/(x-y)√(xy)÷[(√x+√y)/(x-y)]=√(xy)×[(x-y))/(√x+√y)]=√(xy)×[(√x+√y)(√x-√y)/(√x+√y)]=√(xy

化简x/(根号x+y)

化简x/(根号x+y)上下同乘以√(x+y)原式=x*√(x+y)/[√(x+y)]²=x√(x+y)/(x+y)

y=根号【x+根号(x+根号x)】求导

y=根号【x+根号(x+根号x)】求导

(根号x+根号y-1)(1-根号y+根号x),其中x=3根号2,

(根号x+根号y-1)(1-根号y+根号x),其中x=3根号2,(√x+√y-1)(√x-(√y-1))=(√x)-(√y-1)=3-(√2-1)=2√2.

化简:((根号x-根号y)^3+2x根号x+y根号y)/(x根号x+y根号y)+(3根号xy-3y)

化简:((根号x-根号y)^3+2x根号x+y根号y)/(x根号x+y根号y)+(3根号xy-3y)/(x-y)题是这样的吧:[(√x-√y)^3+2x√x+y√y]/(x√x+y√y)+[3√(xy)-3y]/(x-y)原式=[(x√x-

5的根号x³y-y根号4xy-6根号xy+x根号y/x-根号x/y

5的根号x³y-y根号4xy-6根号xy+x根号y/x-根号x/y5的根号x³y-y根号4xy-6根号xy+x根号y/x-根号x/y=5x√xy-2√xy-6√xy+√xy-1/y·√xy=(5x-2-6+1-1/y)√

化简:(x-y)除以(根号x+根号y)-(x-2根号xy+y)除以(根号x-根号y)

化简:(x-y)除以(根号x+根号y)-(x-2根号xy+y)除以(根号x-根号y)可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²

4x-y/2根号x+根号y 9x-6根号xy+y/3根号x-根号y

4x-y/2根号x+根号y9x-6根号xy+y/3根号x-根号y1、4X-Y=[2根号x+根号y]乘以【2根号x-根号y】所以等于2根号x-根号y考验平方差公式的逆用2、4x-y/2根号x+根号y=【3根号x-根号y】的平方所以等于3根号x