log(a+b)

log(ab)=log(a)+log(b)吗我知道log(a)+log(b)=log(ab),那反过来呢?那log(a)(X)=clog(b)(X)=d用c、d表示log(ab)(X)怎么做呢。对,一样正确我晕啊，等号两边的式子是等价的，你

log(a)(b)=log(c)(b)/log(c)(a)怎么证log(a)(b)=log(c)(b)/log(c)(a)怎么证若有对数log（a）（b）设a=n^x,b=n^y则log（a）（b）=log（n^x）(n^y)根据对数的基本

化简log(1/a)b+log(a)b换底公式原式=lgb/lg(1/a)+lgb/lga=lgb/lg(a^-1)+lgb/lga=lgb/(-lga)+lgb/lga=-lgb/lga+lgb/lga=0log(1/a)b+log(a)

log(a)(b)与log(b)(a)是什么关系由换底公式log(a)(b)=log(b)/log(a)log(b)(a)=log(a)/log(b)即二者互为倒数

公式：log(a)(b)*log(b)(a)=?log(a)(b)*log(b)(a)=1log(a)(b)*log(b)(a)=logb/loga*loga/logb=1

2^(log(a)(b))*8^(log(a)(b))16^log((a)(b))

已知01比较log(a)(1/b),log(a)(b),log(b)(1/b)的大小LOG函数是个单调函数,所以只需要比较a/b,ab,1的大小就可以了.很明显有：a/ba/b.如果LOG函数底数小于1,是个减函数,大小关系和上面的相反如果

已知01.比较loga1/b,logab,logb1/b的大小. 发了图片,最快回答,画出log的函数图，由a，b的值画出大致区间就可以看出来了。

求证log(a)^(b)=1/log(b)^(a)求证log(a)^(b)=1/log(b)^(a)换底公式:logab=logbb/logba=1/logba

若|loga1/4|=loga1/4,|logba|=-logba则ab满足什么条件0＜a＜1b＞1log旁边的a在下面第一个等式取绝对值与原数相等,所以此数的数值为正,所以0第二个等式取绝对值与原数相反,所以此数的数值为负,所以b>1.|

对数转换log(1/b)(a)可化为-logb(a)log(1/a)(b)可化为-loga(b)看不懂怎么转换的,设log(1/b)(a)=t,那么由对数的定义可以知道(1/b)^t=a,即b^(-t)=a,所以logb(a)=-t,即-l

log(a)(b)+log(a)(c)可以等于什么log(a)(b)+log(a)(c)=㏒a↑(bc)

matlab中合并对数?如何实现log(a)-log(b)=log(a/b)使用simple或者simplify函数

证明log^a+log^b=log^(a+b)要过程(我当你底数是10,其他底数证明方法也一样的)设lga=m,lgb=n则a=10^m,b=10^nab=10^(m+n)即lgab=m+n=lga+lgb我记得初中课本上面的对数这章有详细

log(a)b=log(c)b/log(c)a是怎么推算来的log(a)b=log(c)b/log(c)a把log(c)a乘到左边,变成log(a)b*log(c)a=log(c)b,只要证这个式子就行了.两边都以c为底求幂,c^(log(

a^[log(a)b×log(b)c×log(c)N]求值a^[log(a)b×log(b)c×log(c)N]=a^[lgb/lga×lgc/lgb×lgN/lgc]=a^(lgN/lga)=a^(logaN)=N

求对数的解答题!求值.log(b)A*log(c)B*log(a)Clog(b)A*lob(c)B*lob(a)C=(lnA/lnb)*(lnB/lnc)*(lnC/lna)若A=a,B=b,C=c,则原式=lna*lnb*lnc/(lna

1、若a²>b>a>1,则log(b)b/a,log(b)a,log(a)b从小到大排列依次顺序是?2、若2^x=3^y=5^z,且x、y、z都是正数,则2x,3y,5z从小到大依次排列顺序是?尤其是思路和过程~感谢ing……思路

若a²>b>a>1,试比较logbb/a,logba,logab的大小logbb/a-logba=logb(b/a²)∵a²>b>a>1∴b/a²1∴logab>logba∴logab>logba>l

2log(b)x=log(a)x+log(c)x求证,c^2=(ac)^[log(a)b]2log(b)x=log(a)x+log(c)x2lgx/lgb=lgx/lga+lgx/lgc把lgx约分2/lgb=1/lga+1/lgc=(lg