求z=e^xy的全微分

z=e^xy的全微分z=e^xydz=de^xy=e^xy*dxy=e^xy*(ydx+xdy)

求z＝e∧（xy）的全微分dz=e^(xy)(ydx+xdy)

求函数z=e^xy*cos(x+y)的全微分dz我来试试吧...z=e^xy*cos(x+y)Z'x=ye^xycos(x+y)-e^xysin(x+y)Z'y=xe^xycos(x+y)-e^xysin(x+y)故dZ=[ye^xycos

求二元函数Z=e^xy在点（1,2）处的全微分Z=e^xy在x处的导函数为ye^(xy)在y处的导函数为xe^(xy)dz=ye^(xy)dx+xe^(xy)dy=2e^2dx+e^2dydz=αz△x/αx+αz△y/αy=ye^(xy)

一道微积分题,求Z=e^(sin(xy))的全微分.∂z/∂x=e^sin(xy)*cos(xy)*y∂z/∂y=e^sin(xy)*cos(xy)*x所以dz=ycos(xy)*e^sin(

求z=In(xy)+e^(x+y^2)的全微分

求函数z=arctan(xy)的全微分.首先对x求偏导数得到のz/のx=1/(xy)^2*y接着对y求偏导数得到のz/のy=1/(xy)^2*x所以dz=のz/のx*dx+のz/のy*dy=1/(xy)^2*ydx+1/(xy)^2*xdy

求函数z=(1+xy)^y的全微分,lnz=yln(1+xy)Z'x/z=y^2/(1+xy)--->Z'x=zy^2/(1+xy)Z'y/y=ln(1+xy)+xy/(1+xy)--->Z'y=zln(1+xy)+xyz/(1+xy)dz

求二元函数z=xy的全微分答案是ydx+xdy

z=sin(xy)的全微分dz=cos(xy)xdy+cos(xy)ydx

全微分(多元函数)求z=e^xy+x^2在点（1,2）的全微分.（注:^符号是次方的意思.）请问有哪位大神会做的,求指教!

求一道微分题求函数z=xy+(x/y)的全微分dz=(y+1/y)dx+(x-x/y^2)dy

设Z=F(X,Y)是由方程E^Z-Z+XY^3=0确定的隐函数,求Z的全微分Dz对方程两边求全微分得：(e^z-1)dz+y^3dx+3xy^2dy=0（方法和求导类似）移项,有dz=-(y^3dx+3xy^2dy)/(e^z-1)

求由方程x+y+z=e∧–(x+y+z)所确定的隐函数z=z(xy)的全微分对x求偏导:dx+z'*y*dx=(e^-(x+y+z))*-(dx+z'*ydx)(dx+z'*y*dx)*(e^-(x+y+z)+1)=0对y求偏导:dy+z'

求Z的全微分：Z=arcsin（xy）Z=xsin(x+y)Z=arcsin(xy)Z'xy=1/√(1-(xy)^2)(xy)'x=y(xy)'y=xdZ=Z'xy*(xy)'xdx+Z'xy*(xy)'ydy=ydx/√(1-(xy)^

高数求全微分求函数z=arctan(x+y)/(1-xy)的全微分设z=arctanu/v,而u=x+y,v=1-xy所以dz=[1/(1+(u/v)^2)×(1/v)]du+[1/(1+(u/v)^2)×(-u/v^2)]dv又因为du=

z=f(xy,y)求dz求Z的全微分令u=xyv=yz=f(u,v)dz=f1`du+f2`dvdu=xdy+ydxdv=dy代入,有dz=f1`(xdy+ydx)+f2`dy=y*f1`dx+(x*f1`+f2`)dy其中的f1`,f2`

matlab高手,设z=xy+x/y,求z的全微分.symsxyz=x*y+x/ya=diff(z,x)a=y+1/yb=diff(z,y)b=x-x/y^2dz=dx*a+dy*b=dx*(y+1/y)+dy*(x-x/y^2)

设Z=e的xy次方,则全微分dzdz=ye^(xy)dx+xe^(xy)dy

w=f(e^x/y,z/xy)的全微分是多少u=(e^x)/y∂u/∂x=(e^x)/y∂u/∂y=-(e^x)/y^2du=(∂u/∂x)dx+(∂u/&