sin^2x+cos^2x

化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)

已知tan=2,求(cosx+sinx)/(cosx-sinx)+sin^2xsinx=2cosx,sin^2x=4cos^2xsin^2x=4-4sin^2x,sin^2x=4/5(cosx+sinx)/(cosx-sinx)+sin^2

化简(sinx+cosx-1)(sinx-cosx+1)/sin2xsinx=2sin(x/2)cos(x/2)cosx=1-2sin^2(x/2)故sinx+cosx-1=2sin(x/2)[cos(x/2)-sin(x/2)]sinx-

已知向量a=(sinx,cosx+sinx),b=(2cosx,cosx-sinx),x∈R,设函数f(x)=ab（1）求函数f（x）的最大值及相应的自变量X的取值集合.（2）当x属于（0,π/8）,且f（x）=5分之4根号2时,求f（x+

2cosx(sinx-cosx)+12cosx(sinx-cosx)+1=2sinxcosx-2cosx^2+1=sin2x+1-2cosx^2=sin2x-cos2x=√2sin(2x-π/4)直接打开括号，1-2cx=-c2x2cs=s

y=2cosx(sinx+cosx)先采纳呀

化简sin(x)cos(x)cos(2x)sin(x)cos(x)cos(2x)=1/2sin(2x)cos(2x)=1/4sin(4x)1/4sin4x

化简sin(x)cos(x)cos(2x)1/2sin2x*cos2x=1/4sin4x

sinxcosxcos2x化简是乘法吗?若是(sinx)(cosx)(cos2x)=(0.5sin2x)(cos2x)=0.5(sin2x)(cos2x)=0.25sin4x

(sin^2x+cos^2x)(sin^2x-cos^2x)怎么得sin^2x-cos^2x?sin^2x+cos^2x=1

(sinx*sin3x)sin^2x+（cosx*cos3x)cos^2x如何变到1/2[(cos2x-cos4x)sin^2x+(cos2x+cos4x)cos^2x]sinx*sin3x=(1/2)[cos(x-3x)-cos(x+3x

已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=?sinx+3cosx=2,①(sinx)^2+(cosx)^2=1.②由①,sinx=2-3cosx,③代入②,10（cosx)^2-12co

化简cos^2(x)*sin^2(x)-sin^2(x)=sin^2(x)*[cos^2(x)-1]=-sin^4(x)

化简cos^(2)(x)*sin^(2)(x)-sin^(2)(x)

化简sin^4x-sin^2x+cos^2xsin^4x-sin^2x+cos^2x=sin^2x(sin^2x-1)+cos^2x=-sin^2xcos^2x+cos^2x=cos^2x(1-sin^2x)=cos^4x=sin^4x-2

化简:sin^4x-sin^2x+cos^2xsin^4x-sin^2x+cos^2x=sin^2x(sin^2x-1)+cos^2x=-sin^2xcos^2x+cos^2x=cos^2x(-sin^2x+1)=cos^4x

已知函数y=(sinx+cosx)(sinx+cosx)+2cosx*cosx,求它的递减区间语气亲和、态度友好整理方程,得y=1+2sinxcosx+2(cosx)^2利用降幂公式和二倍角公式,得y=sin2x+cos2x+2再利用辅助角

sin(x/2)cos(x/2)=sin（x）/2无误sin的二倍角公式sin(x)=2sin（x）cos（x）反过来用的

化简sin^4x+cos^2x(7+cos4x)/8主要利用了降幂公式sin^2x=(1-cos2x)/2cos^2x=(1+cos2x)/2你试试看

sin[cos^2(x^3+x)],求导=cos[cos^2(x^3+x)]×[cos^2(x^3+x)]'=cos[cos^2(x^3+x)]×2cos(x^3+x)[cos(x^3+x)]'=-cos[cos^2(x^3+x)]×2co