sec2x+csc2x

integratetan2x-sec2x/2(tan2x)^2dx见图

化解三角函数!sec3x-sec2x-secx+13和2是指数secx^3-secx^2-secx+1=secx(secx^2-1)-(secx^2-1)=(secx-1)(secx^2-1)=(secx-1)tanx^2=secxtanx

[1＋sin2x]/(cos2x)=tan2x＋sec2x这是为什么左边=1/cos2x+sin2x/cosx=sec2x+tan2x=右边命题得证

设f(x)=tan(x²+1)sec2x,则f´(x)=f'(x)=[tan(x²+1)]'sec2x+tan(x²+1)(sec2x)'=sec²(x²+1)*(x²

f(x)=tan(x^2+1)sec2x求f'(x)这个~2xsin²(x²+1)cos2x+2sin(x²+1）cos(x²+1)sin2xf'(x)=-----------------------

已知函数y=2sin2x+csc2x+tanx+cotx,x属于(0,90°),求y得最小值,有如下解法2sin2x+csc2x=2sin2x+1/sin2x>=2根号2,tanx+1/tanx>=2,两式相加得y>=2根号2+2,所以ym

高一数学三角函数最小值y=2sin2x+csc2x+tanx+cotxx属于0到π/2求y最小值x属于(0,π/2)则2x属于(0,π)sin2x属于(0,1),2sin2x属于(0,2)csc2x属于(-1,1),tanx属于(0,正无穷