若实数xyz满足

若实数xyz满足(x-z)²-4(x-y)(y-z)=0,则xyz之间的关系是怎样的原等式可变为：(x-y+y-z)^2-4(x-y)(y-z)=0=>(x-y)^2+2(x-y)(y-z)-4(x-y)(y-z)+(y-z)^2

若实数xyz满足(x-z)²-4(x-y)(y-z)=0,则xyz之间的关系是怎样的x+z-2y=0

若实数xyz满足x等于4—y,z平方等于xy—4求证x等于yz²=xy-4=(4-y)y-4∴z²+y²-4y+4=0即z²+(x-2)²=0于是,z=x-2=0∴x=2∴4-y=2∴y=2

若实数xyz满足x=6-y,z^2=xy-9.求证x=y快把x=6-y代入z²=xy-9,可得z²=（6-y）y-9即z²=-（y²-6y+9）即z²=-（y-3）²所以z=y-3

若实数xyz满足x²+y²+z²-xy-yz-xz=8,用A表示绝对值x-y,绝对值y-z.绝对值z-x中的最大值,则A最大为答：x²+y²+z²-xy-yz-xz=8两边同时乘以

若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是()若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是()为什么?A.x+y+z=0B.x+y—2z=0C.y+z—2x=0D.z

非零实数xyz,满足x+y+z=xyz,x平方=yz,求证x平方大于等于3∵x^2=yz∴x+y+z=xyz=x^3x^3-x=y+z≥2根号（yz）=2|x|x（x^2-1）≥2|x|当x＜0时,x（x^2-1）≥-2xx^2

若实数xyz满足(x-2y+z)^2+4(x-y)(y-z)=0Axy-yz=0Bxy+yz=0Cxy-xz=0Dxy+xz=0各项剩做运算,得x²-2xz+z²=0所以（x-z）²=0x=z所以选AA就是（x

若正实数xyz满足x+y+z=4xy+yz+zx=5则x＋y的最大值是!设t=x+y.∵x+y+z=4,∴z=4-(x+y)=4-t.又∵xy+yz+zx=5,∴xy=5-z(x+y)=5-zt=5-(4-t)t=5-4t+t².

若实数x,y,z满足条件√x+√y-1+√z-2=1/4(x+y+z+9),求xyz的值√x+√(y-1)+√(z-2)=1/4(x+y+z+9)4√x+4√(y-1)+4√(z-2)=x+y+z+9x-4√x+(y-1)-4√(y-1)+

若实数XYZ满足(X-Z)-4(X-Y)(Y-Z)=0则下列式子一定成立的是1楼A.X+Y+Z=0B.X+Y-2Z=0C.Y+Z-2X=0D.Z+x-2Y=0设X-Y=a,Y-Z=b由题意得(a+b)^2-4ab=(a-b)^2=0∴a=b

若实数X.Y.Z满足X+1/Y=4,Y+1/Z=1,Z+1/X=7/3,则XYZ的值为-------X+1/Y=4Y+1/Z=1Z+1/X=7/3消元后得到二元二次方程组,解得：X=3/2,Y=2/5,Z=5/3所以XYZ=1方程解起来挺烦

若实数XYZ满足(X-Z)-4(X-Y)(Y-Z)=0则下列式子一定成立的是A.X+Y+Z=0B.X+Y-2Z=0C.Y+Z-2X=0D.Z+x-2Y=0不要抄其他相同问题的答案不要设A设B【题中(X-Z)少了平方,否则当X=3/2、Y=3

若实数x、y、z满足x+1/y=4,y+1/z=1,z+1/x=7/3,则xyz的值为多少(X+1/Y)(Z+1/X)(Y+1/Z)=XYZ+1/(XYZ)+X+Y+Z+1/X+1/Y+1/Z=XYZ+1/(XYZ)+4+1+7/3=4*1

若实数X`Y`Z满足x+(1/y)=4,y+(1/z)=1,z+(1/x)=7/3求xyz的值/为除号三式相乘等到：[x+(1/y)]*[y+(1/z)]*[z+(1/x)]=xyz+y+1/z++x+1/y+z+1/x+1/xyz=xyz

若实数x,y,z满足x+y+z-2(xy+yz+zx)+4xyz=1/2,证明x,y,z中至少有一个等于1/2证明：因为x+y+z-2(xy+yz+zx)+4xyz=0.5两边同时乘以2得2x+2y+2z-4xy-4yz-4zx+8xyz=

若实数XYZ满足方程组XY除以（X+2Y）=1YZ除以(Y+2Z）=2ZX除以(Z+2X)则有（A)X+2Y+3Z=0(B)7X+5Y+2Z=0(C)9X+6Y+3Z=0(d)10X+7y+Z=0选哪一个?急用!ZX除以(Z+2X)=3选D

若实数x,y,z满足x+y/1=4,y+z/1=1,z+x/1=3/7,则xyz的值为多少依题意得：X+Y=4/1①Y+Z=1②Z+X=7/3③由②-①得：Z-X=4/3④由④+③得：Z：56/33由③-④得:X：-56/9∴y=56/23

若实数XYZ满足方程组XY除以（X+2Y）=1YZ除以(Y+2Z）=2ZX除以(Z+2X)则有10X+7y+Z=0

若实数x,y满足根号x+根号y-1+根号z-2=4分之1(x+y+z+9),求xyz的值√x+√(y-1)+√(z-2)=(x+y+z+9)/44√x+4√(y-1)+4√(z-2)=x+y+z+9x-4√x+y-4√(y-1)+z-4√(