x+y+z=0

x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0）,求x+y+z分之x+y-z令(y+z)/x=(z+x)/y=(x+y)/z=ky+z=kxx+z=kyx+y=kz2(x+y+z)=k(x+y+z)2(x+y+z)=k(x+y

分式加减法：已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z3

已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z的步骤(x+y)/z=(x+z)/y=(y+z)/x每项加1得到(x+y+z)/z=(x+y+z)/y=(x+y+z)/xx+y+z≠0,所以x=y=z因此(

已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z的步骤令x+y/z=x+z/y=y+z/x=kx+y=zk...（1）x+z=yk...（2）y+z=xk...（3）三式相加：2(x+y+z)=(x+y+z

已知：4x-5y+2z=0x+4y-3z=0则：(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.4x-5y+2z=0（1）x+4y-3z=0（2）（2）×4-（1）得21y=14z即y=2z/3代入（2）得x=z/3∴z=

以知x+y-z/z=x-y+z/y=-x+y+z/x且xyz不等于0,则(x+y)(y+x)(z+x)/xyz=x+y-z/z=x-y+z/y=-x+y+z/x=kx+y=z(k+1)y+z=x(k+1)x+z=y(k+1)2x+2y+2z

X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0X/(Y-Z)=-Y/(Z-

x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值令P=待求值计算得xp+yp+zp=(x^2/z+y)+(y^2/x+z)+(z^2/x+y)+x+y+z=0+x+y+z=

已知x+y+z=0求证x*x*x+y*y*y+z*z*z=3xyz题意即要求证X^3+Y^3+Z^3-3XYZ=0证明如下：x^3+y^3+z^3-3xyz=（x+y+z)(x^2+y^2+z^2-xy-yz-zx)因为X+Y+Z=0,所以

已知:(x2:z+y)+(y2:x+z)+(z2:x+y)=0,求(x:z+y)+(y:x+z)+(z:x+y)的值.走过路过,千万不要错过!

证明：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中x,y,z>0x/(y+z)+y/(x+z)+z/(x+y)>=3/2设S=x+y+zx/(y+z)+y/(x+z)+z/(x+y)=S/(y+z)+S/(x+z)+S/(x

已知（Y+Z）/X=(Z+X)/Y=(X+Y)/Z(X+Y+Z≠0)求分式（X+Y-Z）/(X+Y+Z)的值图片上有答案

已知X+Y+Z=0,求（X+Y)(Y+Z)(X+Z)+XYZ的值.X+Y+Z=0X+Y=-ZY+Z=-XX+Z=-Y所以（X+Y)(Y+Z)(X+Z)+XYZ=(-Z)*(-X)*(-Y)+XYZ=-XYZ+XYZ=0（X+Y)(Y+Z)(

已知x+y+z=0,求(x+y)(y+z)(z+x)+xyz的值x+y+z=0=>x+y=-z=>y+z=-x=>z+x=-y所以(x+y)(y+z)(z+x)+xyz=-xyz+xyz=0x+y=-z,y+z=-x,z+x=-y(x+y)

已知x+y+z=0,求(x+y)(y+z)(x+z)+xyz的值因为x+y+z=0,所以x+y=-zy+z=-xx+z=-y(x+y)(y+z)(x+z)+xyz=-z*(-x)*(-y)+xyz=-xyz+xyz=0根据条件x+y=-zy

已知x>0,y0,且|x||z|,化简|x+z|=|y+z|-|x+y|请列出清楚的算式和布奏和理由因为x>0,z>0；x+z>0所以x+z|=x+z因为y0,|y|>|z|,y+z0,yx+z=y+z+x-yx+z=z+x

若xy-z=0,且(y+x)/x=(z+x)/y=(y+x)/z,求[(y+z)(z+x)(x+y)]/xyz的值?1∵xy-z=0∴xy=z,又∵(y+x)/x=(z+x)/y=(y+x)/z,∴x=y=xy∴x=y=z=1或0又因0不可

已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz的值.(x+y-z)/z=(y+z-x)/x=(z+x-y)/y[x+y]/z-1=[y+z]/x-1=[z+x]/y-

(x+y-z)(x-y+z)=[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊

已知x>0y>0z>0求证(y/x+z/x)(x/Y+z/y)(x/z+y/z)>=8如题.y/x+z/x>=2(根号下yz)/x.x/y+z/y>=2(根号下xz)/y.x/z+y/z>=2(根号下xy)/z.将三个不等式的左右都相乘左边