e^-xy^2dx作业帮

设e^xy-xy^2=Siny,求dy/dx你好!两边对x求导：e^(xy)*(y+xy')-y^2=y'cosy解得y'=(y^2-ye^(xy))/(xe^(xy)-cosy)

xy+e的平方+y=2,求dy/dx对方程取导数y+x(dy/dx)+(dy/dx)=0(dy/dx)(x+1)=-ydy/dx=(-y)/(x+1)

siny+e^x-xy^2=0,求dy/dxsiny+e^x=xy^2,两边求微分,cosydy+e^xdx=d(xy^2)cosydy+e^xdx=y^2dx+2xydy整理,得(e^x-y^2)dx=(2xy-cosy)dydy/dx=

sin(xy)+y^2-e^2求dx/dysin(xy)+y^2-e^2=0求dx/dy三种方法1式中同时对x求导-（y+xy‘）cosxy+2yy'=0解出y’2式中同时取微分d{sin(xy)+y^2-e^2}=dsin(xy)+dy^

e^y+xy=e求d^2y/dx^2｜x=0求详解

由2xy+e∧x-e∧y=0求dy/dx

已知e^y+e^x-xy^2=0,求dy/dx高等数学求导y'e^y+e^x-y²-2xyy'=0y'=(e^x-y²)/(2xy-e^y)即：dy/dx=(e^x-y²)/(2xy-e^y)祝你开心!希望能帮

求导：xy=x-e^xy,求dy/dx答：xy=x-e^(xy)e^(xy)=x-xy=x(1-y)两边对x求导：(xy)'e^(xy)=1-y-xy'(y+xy')e^(xy)=1-y-xy'ye^(xy)+xy'e^(xy)+xy'=1

求导dy/dx及微分xy=e^xy+5两端对x求导得y+xy'=e^(xy)*(y+xy')整理即可得dy/dx=y两边同时微分：d（xy）=d（e^xy）即：ydx+xdy=ye^xydx+xe^xydyy(1-e^xy)dx=x(e^x

由方程xy^2-e^xy+2=0确定的隐函数y=y(x)的导数dy/dx（e^xy是e的xy次方）x（y^2）-e^xy+2=0两端同时求导：(y^2+2xy'y)-e^xy(y+xy')=0集项：(2xy-xe^xy)y'=(ye^xy-

微分方程dy/dx-2xy=e^x^2cosx的通解直接使用通解公式:y=e^(x^2)(C+亅cosxdx)=e^(x^2)(C+sinx)

e^(xy)-(x^2)+(y^2)=1,求dy/dxe^(xy)-(x^2)+(y^2)=1两边同时对x求导,得e^(xy)*(y+xy')-2x+(2yy')=0[xe^(xy)+2y]y'=2x-ye^(xy)dy/dx=[2x-ye

已知xy-e^y=0,求d^2y/dx^2xy-e^y=0y+xdy/dx-e^y·dy/dx=0dy/dx=y/(e^y-x)d²y/dx²=[dy/dx·(e^y-x)-y(e^y·dy/dx-1)]/(e^y-x)

e^x=cosy-xy^2,求dy/dx|x=0这是隐含数求导,两边先对x求导,e^x=-y'siny-(y^2+x2yy'),整理得y'=-(y^2+e^x)/(siny+2xy),把x=0代入,得y'|x=0=-(y^2+1)/siny

e^xy+x+y=2求dy/dx|x=1f(x,y)=e^xy+x+y=2求全微分(Df/Dx)dx+(Df/Dy)dy=0dy/dx=-(y*e^xy+1)/(x*e^xy+1)如果x=1dy/dx|x=1=-(ye^y+1)/(e^y+

求隐函数的偏导数siny+e^x-xy^2=0,求dy/dx解两边求导y‘cosy+e^x-y^2-2xyy'=0即y’(cosy-2xy)=y^2-e^xy'=(y^2-e^x)/(cosy-2xy)或者F(x,y)=siny+e^x-x

设siny-e^x+xy^2=0,求dy/dxsiny-e^x+xy^2=0cosy.y'-e^x+2xy.y'+y^2=0(cosy+2xy)y'=e^x-y^2y'=(e^x-y^2)/(cosy+2xy)

求微分方程(e^x²)dy/dx+2xy（e^x²）=x的通解如下：(e^x²)dy加2xy(e^x²)dx=xdxd((e^x²)y)=xdx通解:(e^x²)y=x^2/2加C

xy=e^(x+y)求dy/dxxy=e^(x+y)求dy/dx这是隐函数求导问题：正统方法是用：隐函数存在定理来做；另一方法是等式两边对x求导,再解出y'来：方法1：f(x,y)=xy-e^(x+y)=0dy/dx=-f'x/f'yf'x

求dy/dx+y/x=e^(xy)令e^(xy)=u,y=lnu/xDy/dx=[(x/u)*(du/dx)-lnu]/x²,∴(1/ux)*(du/dx)-lnu/x²+lnu/x²=u即du/u²