(m+2n+47)(m+47)=mn
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1/M+1/N=5(3M+MN+2N)/(M-MN=3N)M-MN=3N->M=3N/(1-N)代入1/M+1/N=5(3M+MN+2N)/(M-MN)化简为:N^2+15N-1=0解一元二次方程得N(两解)代入M=3N/(1-N),得M
急2[mn+(-3m)]-3(2n-mn),m+n=2mn=-32[mn+(-3m)]-3(2n-mn)=2mn-6m-6n+3mn=5mn-6m-6n=5mn-6(m+n)m+n=2mn=-3=-15-12=-27
M-n=2m+n=5Mn?m=二分之七,n=二分之三
已知m-n=4,m、n互为倒数求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4m+mn)的值m、n互为倒数mn=1(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m
已知mn-n=15,m-mn=6,那么m-mn=6,那么m-n=(),-2mn+m+n()已知mn-n=15,m-mn=6,那么m-mn=6,那么m-n=(),-2mn+m+n()括号里应该填什么已知mn-n=15,m-mn=6,那么m-n
已知mn-n=15,m-mn=6,则m-n=_,-2mn+m+n=_因为(m-mn)+(mn-n)=6+15->m-n=21;(m-mn)-(mn-n)=6-15->-2mn+m+n=-9;所以m-n=21;-2mn+m+n=-9;
已知mn-m=15,n-mn=6则n-m=(),-2mn+m+n=()21,-9把已知的式子左右俩边分别相加得到答案21再分别相减就可以得到-9n-m=(21),-2mn+m+n=(-9)
mn-n=15;m-mn=6那么m-n=();-2mn+m+n=()由题意得m-mn+mn-n=m-nm-mn+mn-n=6+15=21m-mn-(mn-n)=m-mn-mn+n=-2mn+m+nm-mn-(mn-n)=6-15=-9mn-
已知mn-n=20,m-mn=16,则m-n=?,-2mn+m+n=?m-n=(mn-n)+(m-mn)=20+16=36-2mn+m+n=(m-mn)-(mn-n)=16-20=-436,-4m-n=(mn-n)+(m-mn)=20+16
已知m-mn=21,mn-n=15,求m-n与m-2mn+n的值.因为m-mn=21,mn-n=15,所以:m-n=(m-mn)+(mn-n)=21+15=36m-2mn+n=(m-mn)-(mn-n)=21-15=6希望能都帮到你,追问:
已知mn/m+n=2求3m-5mn+3n/-m+3mn-n由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m
已知M+N分之MN=2,求-m+3mn-n分之3m-5mn+3n答:mn/(m+n)=2分子分母同除以mn得:1/(1/n+1/m)=21/m+1/n=1/2(3m-5mn+3n)/(-m+3mn-n)分子分母同除以mn得:=(3/n-5+
已知mn/m+n=2,求3m-5mn+3n/(-m)+3mn-n3m-5mn+3n/(-m)+3mn-n=【3(m+n)-5mn】/【3mn-(m+n)】=【3-5mn/(m+n)】/【3mn/(m+n)-1】=【3-5x2】/【3x2-1
已知mn/m+n=2,求3m-5mn+3n/-m+3mn-n的值由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-1
mn=1m+n=2m=1n=1
m+n=-1mn=-2
【】÷【mn】=2m-3n【2m²n-3mn²】÷【mn】=2m-3n
已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同
已知m-n=2,mn=1,求多项式(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=-6m
已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值错了,第一个是-2mn+2m+3n(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn