求y=1/2sin(2x-1/4π）+1的单调区间周期最值

求y=1/2sin(2x-1/4π）+1的单调区间周期最值

sinx单调区间是(2kπ-π/2,2kπ+π/2)是增函数,在（2kπ+π/2,2kπ+3π/2）上是减函数,周期是2π y=1/2sin(2x-1/4π）+1在(kπ-π/4-π/4,kπ+π/4-π/4)即(kπ-π/2,kπ)是增函数 在（kπ,kπ+π/2）上是减函数,周期是π 最大值是y=1/2+1=3/2,最小值是y=1-1/2=1/2