2sinxcosx

化简2sinxcosx+cos2x2sinxcosx=sin2x2sinxcosx+cos2x=根号2[sin(2x+π/4)]原式＝sin2x+cos2x=2^(0.5)sin(2x+pi/4)2sinxcosx+cos2x=根号2[si

(sinxcosx)^2原函数答：(sinxcosx)^2的原函数=∫(sinxcosx)^2dx=(1/4)∫(sin2x)^2dx=(1/8)∫2(sin2x)^2dx=(1/8)∫1-cos4xdx=x/8-(1/32)*sin(4x

sinxcosx+cosx^2-2化简sinxcosx+cosx^2-2=(1/2)*2sinxcosx+(1/2)*[2*(cosx)^2-1]-(3/2)=(1/2)sin2x+(1/2)cos2x-(3/2)=(√2/2)sin(2x

∫cos2x/(sinxcosx)^2dx∫cos2x/(sinxcosx)^2dx=∫√2cos2x/(2sinxcosx)^2dx=√2/2∫cot2xcsc2xd2x=-(√2/2)csc2x+c

∫dx/(1+sinxcosx)^2令v=tanx,dx=dv/(1+v^2),sinx=v/√(1+v^2),cosv=1/√(1+v^2)∫1/(1+sinxcosx)^2dx=∫1/[1+v/√(1+v^2)*1/√(1+v^2)]^

为什么2sinxcosx=sin2x?这个是个公式

为什么sin2x=2sinxcosxsin(α+β)=sinαcosβ+cosαsinβ,sin2x=sin(x+x)=sinxcosx+cosxsinx=2sinxcosx.由于sin(x+y)=sinxcosy+cosxsiny当y=x

(sinXcosX)^2的不定积分是什么原式=∫1/4*sin²2xdx=∫1/4*(1-cos4x)/2dx=1/32∫(1-cos4x)d4x=x/8-sin4x+C

求y=(1-sinxcosx)/(1+sinxcosx)的值域2/(1+sinxcosx)-1=2/(1+(sin2x)/2)-1这一步咋得到的？只学过诱导公式1-6[1/3,1](1-sinxcosx)/(1+sinxcosx)=2/(1

cos^2+2sinxcosx+sin^2x我是把sin^2x当成sinx的平方来算的,不知道你的意思是不是这样?cos^2x+2sinxcosx+sin^2x=(cosx+sinx)^2=(√2*(√2/2*cosx+√2/2*sinx)

sin2x为何等于2sinxcosxsin2x=sin(x+x)=sinxcosx+cosxsinx=2sinxcosxsin2x=sin(x+x)=sinxcosx+cosxsinx=2sinxcosx

2sinx的平方-2sinxcosx化简2sin²x－2sinxcosx＝1－(1－2sin²x)－sin(2x)＝1－[cos(2x)＋sin(2x)]＝1－√2sin(2x＋45º)应该是sin2x=2si

化简2*(sinxcosx-cos平方x)+12*(sinxcosx-cos平方x)+1=2sinxcosx-2cos²x+1=2sinxcosx-cos2x=sin2x-cos2x=√2sin(2x-45°)你好1.f（X）=s

y=sinxcosx/(2+sinx+cosx)最小值你好!令u=2+sinx+cosx=2+√2sin(x+π/4)∈[2-√2,2+√2](u-2)²=sin²x+cos²x+2sinxcosx=1+2si

化简根号3sinXcosX+cos*2X原式等于（3sinXcosX+cos²x-sin²x）/（sin²x+cos²x）再同时除以cos²x就行了

sinx-2cosx=0,求sinxcosx∵sinx=2cosx∴tanx=2∴sinxcosx=sinxcosx/1=sinxcosx/1+tan^2=tanx/1+tan^2=2/1+4=2/5

y=sinxcosx+cos(2x)化简y=1/2sin2x+cos2x

求2sin2X-SINXCOSX+COS2X的值原式=2(1-cos2x)/2-1/2*(2sinxcosx)+(1+cos2x)/2=3/2-1/2*(sin2x+cos2x)=3/2-√2/2*sin(2x+π/4)哈哈哈哈哈哈哈哈哈哈

化简：y=cos2x+2sinxcosx-sin2xy=cos2x+2sinxcosx-sin2x=cos2x+2sinxcosx-2sinxcosx=cos2x=2(cosx)^2-1

化简-根号3/3sinxcosx+sinx^2f(x)=-√3/3sinxcosx+sin²x=-√3/6sin2x+(1-cos2x)/2=-√3/6sin2x-1/2cos2x+1/2=-√3/3sin(2x+π/3)+1/2